2. Interestingly enough, one of the efforts to break RSA is headed by people who want to watch high definition films on their Linux machines. Based on what I read some months ago, one attack vector concerned the use of a low public exponent (something like e=3) in the AACS Blu-ray standard. This could be seen as a discrete logarithm problem, correct? And are these logarithms harder to solve as the exponent grows?
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